Let X and Y be positive integers. We say that Y is a divisor of X if and only if there is a positive integer Z such that X = Y*Z. You will be given a String[] numbers. Each element in this String[] will contain a positive integer. For each of the given integers compute the sum of its positive divisors, itself excluded. Return a String[] containing the computed sums in the same order, with no unnecessary leading zeroes.

Class: PerfectNumbers Method: sumDivisors Parameters: String[] Returns: String[] Method signature: String[] sumDivisors(String[] numbers) (be sure your method is public)

All the numbers in the input, and all the numbers you should output will fit into 64-bit signed integer variables.

- numbers will contain between 1 and 50 elements, inclusive.
- Each element in numbers contains between 1 and 13 digits ('0'-'9'), inclusive.
- No element in numbers will contain leading zeroes.

0) {"6"} Returns: {"6" } The divisors of 6 (other than 6 itself) are 1, 2, and 3. Their sum is 1+2+3 = 6. 1) {"28"} Returns: {"28" } Divisors of 28 are 1, 2, 4, 7, and 14, and their sum is 1+2+4+7+14 = 28. 2) {"4", "8", "16", "32"} Returns: {"3", "7", "15", "31" } 3) {"13", "47", "997"} Returns: {"1", "1", "1" } 4) {"510510"} Returns: {"1231314" } 510510 = 2*3*5*7*11*13*17 5) {"235152", "235326326132", "1234567890123"} Returns: {"461232", "176530725964", "411987510213" } 6) {"9999999999999"} Returns: {"4903272088641" } This is the largest valid input number. 7) {"1"} Returns: {"0" } And this is the smallest valid input.

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